# Line slope calculator 5x+4y=62

**Straight line given by points A[6; 8] and B[10; 3]**

## Calculation:

**Slope-intercept form of line:**y = -1.25x+15.5

**Canonical form of the line equation:**5x+4y-62 = 0

**Parametric form of the line equation:**

x = 4t+6

y = -5t+8 ; t ∈ R

**Slope:**m = -1.25

**Slope angle of line: φ =**-51°20'25″ = -0.8961 rad

**X intercept:**x

_{0}= 12.4

**Y intercept:**y

_{0}= q = 15.5

**Distance line from the origin:**d

_{0}= 9.6828

**The length of the segment AB: |AB| =**6.4031

**Vector: AB =**(4; -5)

**Normal vector: n =**(5; 4)

**Midpoint of the segment AB: M =**[8; 5.5]

**Perpendicular Bisector equation:**4x-5y-4.5 = 0

**Vector OA = (6; 8) ; |OA| = 10**

**Vector OB = (10; 3) ; |OB| = 10.4403**

**Scalar product OA .OB = 84**

**Angle ∠ AOB = 36°25'51″ = 0.6358 rad**